Compound wall Materials (Bricks, Mortar) Calculator
Input Dimension of Wall and Bricks
How to Estimate No. of Bricks, Cement, and Sand in Compound Wall?
Q) Calculate the Quantity of Bricks, Cement, Sand in a compound wall having Length = 30 feet, Breadth = 20 feet,
Height above the floor of wall = 5 feet with 5” width.
Height below ground = 3 feet with 10” width.
Bricks Size:- 190x90x90 mm
Step1:- Calculate volume of Wall
Above Ground = L x B x H = 100 x 5/12 x 5
= 208.3 Cub. Feet
Below Ground = 100 x 10/12 x 3 = 250 Cub. Feet
Total Volume of Wall = 458.3 Cub. Feet = 12.98 cub. meter
Step2:- Calculate volume of Bricks without Mortar
V.B = L x B x H = 0.190 x 0.09 x 0.09 = 0.001539 cub. Meter
Assume 10 mm thickness of mortar
Step3:- Calculate volume of Bricks with Mortar
V.B = L x B x H = 0.200 x 0.100 x 0.100 = 0.002 cub. meter
Step4:- Calculate no. of bricks
Divide volume of wall by volume of bricks with mortar
N.B = 12.98/0.002 = 6490 Nos.
Step5:- Calculate Wet volume Mortar
V.M = Volume of the wall – No. of Bricks x Volume of one brick without mortar
= 13 – 6500 x 0.001539 = 2.99 = 3 cubic meter Approx.
Step6 :- Calculate Dry volume of the Mortar
Dry Volume of mortar x 1.34 ( Add 32% to 34%)
= 2.99 x 1.34 = 4 cubic meter
Assume ratio of (Cement : Sand) = (1:4)
Step7:- Calculate the volume of Sand and Cement
V.S = Sand Ratio /(1+4) x Dry Volume
= 4/5 x 4 = 3.2 cub. Meter
V.C = Cement Ratio /(1+4) x Dry Volume
= 1/5 x 4 = 0.8 cub. Meter
Weight of cement = Volume x density of cement = 0.8 x 1440 = 1152 Kg.
No. of Bags of Cement = 1152/50 = 23.04 Bags of Cement ( One Bags of cement = 50 Kg.)
|2||Quantity of Sand||3.2 Cub. meter|
|3||Bags of Cement||23.04 Bags.|